O. Aichholzer, A. Fischer, F. F. J. Meier, U. Pferschy, A. Pilz, and
R. Stanek
The traveling salesman problem (TSP) asks for a shortest tour through all
vertices of a graph with respect to the weights of the edges. The symmetric
quadratic traveling salesman problem (SQTSP) associates a weight with every
three vertices traversed in succession. If these weights correspond to the
turning angles of the tour, we speak of the angular-metric traveling salesman
problem (Angle TSP). In this paper, we first consider the SQTSP from a
computational point of view. In particular, we apply a rather basic
algorithmic idea and perform the separation of the classical subtour
elimination constraints on integral solutions only. Surprisingly, it turns
out that this approach is faster than the standard fractional separation
procedure known from the literature. We also test the combination with
strengthened subtour elimination constraints for both variants, but these
turn out to slow down the computation. Secondly, we provide a completely
different, mathematically interesting MILP linearization for the Angle TSP
that needs only a linear number of additional variables while the standard
linearization requires a cubic one. For medium sized instances of a variant
of the Angle TSP this formulation yields reduced running times. However, for
larger instances or pure Angle TSP instances the new formulation takes more
time to solve than the known standard model. Finally, we introduce MaxSQTSP,
the maximization version of the quadratic traveling salesman problem. Here it
turns out that using some of the stronger subtour elimination constraints
helps. For the special case of the MaxAngle TSP we can observe an interesting
geometric property if the number of vertices is odd. We show that the sum of
inner turning angles in an optimal solution always equals

. This implies
that the problem can be solved by the standard ILP model without producing
any integral subtours. Moreover, we give a simple constructive polynomial
time algorithm to find such an optimal solution. If the number of vertices is
even the optimal value lies between 0 and

and these two bounds are
tight, which can be shown by an analytic solution for a regular

-gon.